In this section, you are expected to show the calculation on how to identify the IP address that was assigned for the ULearn System Server based on the information given in the project scenario. Explain the concept and show the calculation to identify the IP address.
In terms of private addressing scheme, UTeM network is using Class C private addressing scheme which is 172.16.0.0/20. In UTeM facilities, 8 faculties and addition of 1 UTeM IT Center. Hence, the network address was segregated by using the subnetting concept. Each department is given their network address. In this case, UTeM IT Center needs to be assigned as their network address. From this network address, the ULearn System server is assigned as the 5th available address. Use this information to identify the address of the ULearn System server.
For UTeM Network, it uses Class B private addressing scheme because we need to support all 500 - 1000 students;
172.16.0.0/20
Subnetting to 8 faculties + 1 UTeM IT Center
To have 8 faculties + 1 UTeM IT Center, we have 9 departments to share, we must find the nearest number which is not too large and not or less from the number in the requirement. In this case, we calculate that 16 is the most suitable. Here is the explanation.
As you can see, we must use 16 because we have 9 subnets. We can’t take 8 subnets because it does not fulfill the 9 subnets in the requirements and from the 4 bits that have been borrowed.
So, 9 ~ 16 = 24
4 Bits need to be borrowed from the Host
172.16.0.0/20
255.255.240.0 is the new subnet mask. We get 240 from here
Refer to table above, we assigned the subnet network address for the UTeM IT Center as 172.16.80.0. The scenario indicates that the ULearn System server is specified as the 5th available address. Therefore, the IP address of the ULearn System server is 172.16.80.6 .We don't start at 172.16.80.1 because it will be configured as the router IP address for this subnet and will become the default gateway. So it will start from 172.16.80.2 and so on.
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